Question

three numbers are in continued proportion, whose mean proportiin is 12 and sum of remaining two numbers is 26,then find the numbers​

Answer 1

The three numbers are

12and26= 12-26

12and26=12

12and26=12diveded into three parts=?

12divided into three parts =3÷12=4

=thus the number of three parts = 8 , 12 , 18

that's it....

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Answer 2

Answer:

The required numbers are 8, 12 and 18 or 18, 12 and 8

Step by step explanation:

Let a, b and c be the three numbers in continued proportion.

Then b = 12 and a + c = 26 ...(1)

b² = ac

=> 12² = ac

=> ac = 144

=> a = 144/c (2)

Substituting a = 144/c from (2) in a + c in (1)

=> 144/c + c = 26

=> 144 + c² = 26c

=> c² - 18c + 8c + 144 = 0

=> c(c - 18) + 8(c - 18) = 0

=> (c - 18) (c + 8) = 0

=> c - 18 = 0

=> c = 18

OR

=> c - 8 = 0

=> c = 8

Now, a + c = 26

=> a = 26 - 18

=> a = 26 - 8

OR, a + c = 26

=> a = 26 - 8

=> a = 18

The required number 8, 12 and 18 or 18, 12 and 8.

Hope it helps :)