Question

Three numbers are in ratio 2:3:4. The sum of their cubes is 33957. Find the numbers. ( In the following image question number 35)

Answer 1

Let the numbers be 2x^3, 3x^3 and4x^3................................................. (2x)^3+ (3x)^3+ (4x)^3= 33957...................................................... 8x^3 + 27x^3+ 64x^3= 33957...................................................... => 99x^3= 33957.......................................... => x^3=33957/99........................................ = x^3= 343................................................... Now take cube root , x= 3√343.................................. x=7...................................... Now put value of x The numbers are Ist number is 2x= 2*7=14............................... 2nd number is 3x = 3*7 = 21....................................... 3rd number is 4x = 4*7 = 28.................................

Answer 2

Answer:

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Step-by-step explanation:

Let the numbers be 2x, 3x and 4x

sum of cubes = 33957

⇒(2x)³ + (3x)³ + (4x)³ = 33957

⇒8x³ + 27x³ + 64x³ = 33957

⇒99x³ = 33957

⇒x³ = 33957/99 = 343

⇒x = ∛343 = 7

Numbers are:

2x = 2×7 = 14

3x = 3×7 = 21

4x = 4×7 = 28