Question

Three numbers are in ratio 3 4 5 and there average are 24.the largest number is

Answer 1

HEYA !

Given that,

3 numbers are in the ratio 3 : 4 : 5

Let the common multiple be k

Then,
Numbers are 3k , 4k and 5k

Also given that,

Average of these numbers = 24

Sum of numbers / Total numbers = 24

→ ( 3k + 4k + 5k ) / 3 = 24

→ 12k / 3 = 24

→ 4k = 24

→ k = 6

Therefore ,

Largest number = 5k = 30

Hence,

The required largest number is 30

Answer 2

Hiii friend,


Ratio of the three numbers are 3:4:5


Let X be multiply to these numbers. Then the numbers becomes 3X , 4X and 5X.


According to question,


3X + 4X + 5X/3 = 24

12X = 24 × 3

12X = 72


X = 72/12 => 6

First Number = 3X = 3 × 6 = 18

Second number = 4X = 4 × 6 = 24

And,


Third Number = 5X = 5 × 6 = 30


Clearly 30 is the largest Number.




HOPE IT WILL HELP YOU..... :-)