Math, asked by yadavpankaj3460, 3 months ago

three numbers are in the 4:5:6.if the sum of the largest and smallest numbers equals the sum of the remaining numbers and 55, find the three numbers?

Answers

Answered by Anonymous

Given :-

Three number are in the ratio of 4:5:6.
The sum of the largest and smallest equals the sum of the third and 55.

To Find :-

Find the numbers

Solution :-

~Here, we’re given that three numbers are in the ratio of 4:5:6, the sum of the largest and smallest equals the sum of the third and 55. We need to find the numbers, firstly we’ll assume the numbers according to the given ratio. Then we’ll form an equation according to the question and after solving that equation we can find the required numbers.

___________

★ Let the numbers be :

According to the question :-

➟ 6x + 4x = 5x + 55

➟ 10x = 5x + 55

➟ 10x – 5x = 55

➟ 5x = 55

➟ x = 55/5

↬ x = 11

Finding the numbers :-

⠀⟶⠀4x = 4 × 11 = 44

⠀⟶⠀5x = 5 × 11 = 55

⠀⟶⠀6x = 6 × 11 = 66

___________

Hence,

The numbers are 44, 66 and 55

Answered by Anonymous

${ \underbrace{ \mathsf{ \orange{Given}}}}$

Three numbers are in the ratio 4:5:6

The sum of the largest and smallest numbers equal the sum of the third numbers and 55

${ \underbrace { \mathsf{ \orange{To \: \: Find}}}}$

The three numbers

${ \underbrace{ \mathsf { \orange{Concept}}}}$

» Here in this query, is given that three numbers are in the ratio 4:5:6, the sum of the largest and the smallest equals the sum of the third and 55.

Here we need to find the three numbers, first we will assume the numbers according to the given ratio. Then We will form an equation according to the query and after solving that equation we will get the required answers.

__________________

${ \underbrace{ \mathsf{ \orange{Solution}}}}$