Question

Three numbers are in the rati0 2:3:5 and their sum is 100

Answer 1

$\huge\it{Given\;:}$

$\huge\it{Ratio's\;:-2:3:4}$

$\huge\it{Sum\;:-100}$

$Solution \: \\ \ let \: the \: number \: be \:x$

$2x + 3x + 5x = > 100 \\ \\ 10x = > 100 \\ \\ x \times \frac{100}{10} \\ \\ x = > 10 \\ \\ now \\ \\ 10 \times 2 = > 20 \\ 10 \times 3 = > 30 \\ 10 \times 5 = > 50 \\ \\ numbers \: are \: 20 \: 30 \: and \: 50$

Answer 2

Step-by-step explanation:

$\underline {\bold{Given :}}$

• Ratio of the numbers = 2:3:5
• Sum of the numbers = 100

$\underline {\bold{To Find :}}$

• The three numbers.

Let

• The first number =2x
• The second number= 3x
• The third number= 5x.

Atq,

$\implies 2x + 3x + 5x = 100 \\ \implies 10x = 100 \\ \implies x = \frac{100}{10} \\ \implies x = 10$

Hence,

• The first number is (2×10)=20
• The second number is (3×10)=30
• The third number is (5×10) =50

$\underline {\bold{Verification:}}$

$\implies 2x + 3x + 5x = 100 \\ \implies 20+30+50= 100 \\ \implies 100= 100$