Question

Three numbers are in the ratio 1:3:5. If the sum
of the cubes of first two numbers is 224 and the
difference of the cubes of the last two numbers is
784, find the three numbers.

Answer 1

Answer:

let the ratio be X

then number will be:

1X , 3X , 5X

A.T.Q

(X^3)+(3X^3)=224

X^3  + 27X^3=224

28X^3=224

X^3=224/28

X^3=8

X=2

5X^3 - 3X^3=784

125X^3 - 27X^3=784

98X^3=784

X^3=784/98

X^3=8

X=2

Step-by-step explanation: