three numbers are in the ratio 2:3:4. if sum of the largest and smallest equals the sum of the third and 33 . find the number
Answers
Answered by
127
Let the common factor be x
4x + 2x = 3x + 33
6x = 3x + 33
6x - 3x = 33
3x = 33
x = 33/3
x = 11
The number is 11.
4x + 2x = 3x + 33
6x = 3x + 33
6x - 3x = 33
3x = 33
x = 33/3
x = 11
The number is 11.
Answered by
141
let ,
the three numbers in the ratio 2:3:4 be 2x, 3x and x respectively
obviously the largest and smallest numbers will be 4x and 2x respectively.
according to the question,
4x + 2x = 3x + 33
⇒6x = 3x +33
⇒6x - 3x = 33
⇒ 3x = 33
⇒x = 33/3
⇒x = 11
the three numbers are,
2x = 2× 11 = 22
3x = 3 ×11 = 33
4x = 4×11 =44
the three numbers in the ratio 2:3:4 be 2x, 3x and x respectively
obviously the largest and smallest numbers will be 4x and 2x respectively.
according to the question,
4x + 2x = 3x + 33
⇒6x = 3x +33
⇒6x - 3x = 33
⇒ 3x = 33
⇒x = 33/3
⇒x = 11
the three numbers are,
2x = 2× 11 = 22
3x = 3 ×11 = 33
4x = 4×11 =44
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