Question

Three numbers are in the ratio 2:3:4. The sum of their cubes is 33957. Find the numbers

Answer 1

let the numbers be 2x, 3x, 4x

atq

8x³ + 27x³+ 64x³= 33957

99x² = 33957

x³ = 343

x= 7

∴ the numbers are 14, 21 and 28

Answer 2

let the number by 2 x 3 x and 4x. a/q:-. (2x)^3+(3x)^3+(4x)^3=33957. 8x^3+27x^3+64x^3=33957
99x^3=33957. x^3=33957/99=>x^3=343
$\sqrt[3]{343} = 7$
x=7 first number =2*7=14; second number =3*7=21; third number =4*7=28.ans...