Question

three numbers are in the ratio 2:3:5 and are such that the sum of their squares is equal to 608 , then find the sum of the numbers​

Answer 1

Answer:

40

Step-by-step explanation:

Define x:

Let the smallest number be 2x

The other two numbers are 3x an 5x

Given that the sum of their squares is equal to 608

(2x)² + (3x)² + (5x)² = 608

4x² + 9x² + 25x² = 608

38x² = 608

x² = 16

x = √16

x = 4

Find the numbers:

2x = 2(4) = 8

3x = 3(4) = 12

5x = 5(4) = 20

Find the sum of these numbers:

Sum = 8 + 12 + 20 = 40

Answer: 40

Answer 2

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