Question

three numbers are in the ratio 2 ratio 3 ratio 4 the sum of their cubes is 33957 find the numbers

Answer 1

Heya !!



Let three numbers are 2X , 3X and 4X.



According to the question,



( 2X)³ + (3X)³ + (4X)³ = 33957



8X³ + 27X³ + 64X³ = 33957



99X³ = 33957



X³ = 33957/99



X³ = 343




X = ³✓343 = 7



First number = 2X = 2 × 7 = 14




Second number = 3X = 3 × 7 = 21


And,


Thrid number = 4X = 4 × 7 = 28.

Answer 2

Let the numbers be 2x, 3x, 4x.

Given that the sum of their cubes is 33957.

= > (2x)^3 + (3x)^3 + (4x)^3 = 33957

= > 8x^3 + 27x^3 + 64x^3 = 33957

= > 99x^3 = 33957

= > x^3 = 343

= > x = 7

The numbers are:

= > 2(7) = 14

= > 3(7) = 21

= > 4(7) = 28.

Therefore, the numbers are 14, 21 and 28

Hope this helps!