three numbers are in the ratio 3:4:5 . if the sum of the largest and the smallest number exceeds the third number by 64,find the numbers.
Answers
Answered by
126
Let the three numbers be 3x,4x and 5x
According to the question
5x+3x = 4x + 64
8x-4x = 64
4x = 64
x = 64/4
x = 16
=> 3x = 3×16 = 48
=> 4x = 4×16 = 64
=> 5x = 5×16 = 80
According to the question
5x+3x = 4x + 64
8x-4x = 64
4x = 64
x = 64/4
x = 16
=> 3x = 3×16 = 48
=> 4x = 4×16 = 64
=> 5x = 5×16 = 80
Answered by
21
Answer:
answer:. 48, 64, 80
Step-by-step explanation:
let let the ratio be x= 3 X + 4 x + 5 x
3x + 5x = 4x + 64
8x=4x + 64
8x-4x=64
4x=64
x=64/4
x=16
3x=16×3=48
4x=16×4=64
5x=16×5=80
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