Question

three numbers are in the ratio 3:4:5 . if the sum of the largest and the smallest number exceeds the third number by 64,find the numbers.

Answer 1

Let the three numbers be 3x,4x and 5x
According to the question
5x+3x = 4x + 64
8x-4x = 64
4x = 64
x = 64/4
x = 16
=> 3x = 3×16 = 48
=> 4x = 4×16 = 64
=> 5x = 5×16 = 80

Answer 2

Answer:

answer:. 48, 64, 80

Step-by-step explanation:

let let the ratio be x= 3 X + 4 x + 5 x

3x + 5x = 4x + 64

8x=4x + 64

8x-4x=64

4x=64

x=64/4

x=16

3x=16×3=48

4x=16×4=64

5x=16×5=80