Question

three numbers are in the ratio 3:4:5. If the sum of the largest and the smallest equals to the sum of third and 52, find the numbers.

Answer 1

Let the numbers are 3x, 4x and 5x

According to the questions
3x+5x=4x+52
=>8x-4x=52
=>4x=52
=>x=52/4=13

now the three numbers are
3x=39
4x=52
5x=65
....hope it helps....

Answer 2

$\circ\circ\circ\circ\underline{\fbox{\fbox{\fbox{\fbox{\fbox{\Large{\underline{\textbf{SOLUTION}}}}}}}}}\circ\circ\circ\circ$

$Since,\:the\:three\:numbers\:in\:ratio\:3:4:5\\\\Let\:us\:consider\:the\:numbers\:to\:be\:3x,4x\:and\:5x\:respectively.\\\\According\:to\:the\:question,\\\\\implies3x+5x=4x+52\\\\\implies8x-4x=52\\\\\implies4x=52\\\\\implies x=\frac{52}{4}=13\\\\\implies x=13\\\\\therefore First\:number=3\times13=39,\\\\Second\:number=4\times13=52\\\\and\:Third\:number=5\times13=65$