Three numbers are in the ratio 3:4:5 respectively. if the sum of the first and third numbers is more than the second number by 52, 5then which will be the largest number
Answers
Answered by
7
Let the common factor be x.
So,the numbers are 3x , 4x and 5x .
3x+5x=4x+52
8x-4x=52
x=52/4
x=13
Largest number=5x
=5*13
=65
The largest number is 65
So,the numbers are 3x , 4x and 5x .
3x+5x=4x+52
8x-4x=52
x=52/4
x=13
Largest number=5x
=5*13
=65
The largest number is 65
Answered by
4
Hi Mate !!
Here's ur ans :-
Let the common factor in the numbers be a
Then the nos. are 3a , 4a , 5a
• sum of the first and third numbers is more than the second number by 52.
3a + 5a = 4a + 52
8a - 4a = 52
4a = 52
a = 52/4
a = 13
The first number is :- ( 3a ) = 39
Second number is :- ( 4a ) = 52
Third number is :- ( 5a ) = 65
65 is the largest number.
♯ To verify
sum of the first and third numbers is more than the second number by 52.
LHS :-
39 + 65
104
RHS :-
52 + 52
104
Since , LHS = RHS
hence , the nos. are correct !!
Here's ur ans :-
Let the common factor in the numbers be a
Then the nos. are 3a , 4a , 5a
• sum of the first and third numbers is more than the second number by 52.
3a + 5a = 4a + 52
8a - 4a = 52
4a = 52
a = 52/4
a = 13
The first number is :- ( 3a ) = 39
Second number is :- ( 4a ) = 52
Third number is :- ( 5a ) = 65
65 is the largest number.
♯ To verify
sum of the first and third numbers is more than the second number by 52.
LHS :-
39 + 65
104
RHS :-
52 + 52
104
Since , LHS = RHS
hence , the nos. are correct !!
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