Question

Three numbers are in the ratio 4:5:6. If the sum of the largest and

smallest exceeds the third number by 55.Find the number.

Answer 1

5x+6x-55=4x
11x-4x=55
7x=55
x=55/7

First no. 4×55/7=220/7
2nd= 275/7
3rd= 330/7

Answer 2

three no.s are in the ratio of 4:5:6.

4x + 6x = 5x +55

10x =5(x +11)
2x =x+11

x=11

the no. is 11