Math, asked by manisha459, 1 year ago

three numbers are in the ratio 5:7:12 and the sum of the first and third numbers is greater than the second by 50. The sum of three numbers is

Answers

Answered by ranjanalok961
28
three numbers are in the ratio 5:7:12
Let three number is 5x ,7x & 12x

=>5x+12x=7x+50
=>17x-7x=50
=>10x=50
=>x=5
Then no is
=>5x=5×5=25
=>7x=7×5=35
=>12x=12×5=60
Sum of no=25+35+60=120

manisha459: a) 130 b) 120 c) 128 d) 125
manisha459: can you explain ?
manisha459: thanks a lot
manisha459: yeah understood. thanks for the timely help
manisha459: hey... can you solve a few other problems
Answered by Hansika4871
2

Given:

Three numbers are in the ratio 5:7:12. The sum of the first and the third numbers is greater than the second by 50.

To Find:

The sum of the three numbers is?

Solution:

1. The ratio of the three numbers is 5:7:12.

2. Let the three numbers be 5x, 7x, and 12x.

3. The sum of the first and third numbers is greater than the second by 50,

=> 5x + 12x = 7x + 50, (solve the equation for value of x),

=> 17x  = 7x + 50,

=> 17x - 7x = 50,

=> 10x = 50,

=> x = 50/10,

=> x = 5.

4. The three numbers are 5x5, 7x5, 12x5,

=> The three numbers are 25, 35, 60.

=> The sum of the three numbers are 25 + 35 + 60,

=> The sum of the three numbers is 120.

Therefore, the sum of the three numbers are 120.

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