Three numbers are in the ratio of 1:2:3 their sum of their cubes are 7776 find the numbers
Answers
Answered by
20
Since the numbers are in the ratio 1:2:3.
So suppose the numbers are x, 2x and 3x.
So sum of the numbers = x + 2x + 3x = 7776
⇒6x = 7776
⇒x =
7776
6
= 1296
Therefore the numbers are 1296, 1296×2
= 2592 and 1296×3 = 3888
So suppose the numbers are x, 2x and 3x.
So sum of the numbers = x + 2x + 3x = 7776
⇒6x = 7776
⇒x =
7776
6
= 1296
Therefore the numbers are 1296, 1296×2
= 2592 and 1296×3 = 3888
Answered by
31
Let the three numbers be 1x,2x and 3x
sum of their cubes =7776
(1x+2x+3x)³=7776
1x+8x+27x=7776
36x=7776
X=7776/36
X=216
The three numbers are 216,432,648
Hope this answer helps you.....
sum of their cubes =7776
(1x+2x+3x)³=7776
1x+8x+27x=7776
36x=7776
X=7776/36
X=216
The three numbers are 216,432,648
Hope this answer helps you.....
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