Question

three numbers are such that ratio between them 3:5 if each is increased by 10 the ratio between the new numbers so formed is 5:7 find the original number

Answer 1

let the no in ratio be 3x and 5x
each increased by 10
3x+10
5x+10
the no is formed 5/7
a/q

$\frac{3x + 10}{5x + 10} = \frac{5}{7} \\ 7(3x + 10) = 5(5x + 10) \\ 21x + 70 = 25x + 50 \\ 21x - 25x = 50 - 70 \\ - 4x = - 20 \\ x = \frac{ - 20}{ - 4} \\ x = 5$
hence, the no is3x(3*5=15)and5x (5*5=25)

hope it help you