Math, asked by harithat124, 1 day ago

Three numbers are written as (10a + 1), (1Ob + 2), and (10c + 3), respectively. What will be the unit digit in the product of the squares of the given numbers?​

Answers

Answered by hkb03student
0

Answer:

6

Step-by-step explanation:

Any number multiplied by 10 will have unit place value as 0. So 10a+1 will have in unit place the number 1 (0+ 1 = 1). Similarly, 10b+2 will have in unit place value 2(0+2=2 and 10c+3 will have unit place value 3(0+3=3). The square of 10a+1 will have unit place value 1 (1 square = 1) . Similarly, square of 10b+2 will have unit place value 4 (2 square = 4) and 10bc+3 will have unit place value 9(3 square = 9).

The final product of squares of three numbers will be determined by product of 1×4×9 = 36. There for 6 will be the unit place value of the final product.

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