Three numbers arein1:2:3 if the sum of their cube is 62208, find the number
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Answered by
32
Since the numbers are in ratio 1:2:3 we have,
X:2X:3X=1:2:3
Given that ,
(X)^3+(2x)^3+(3x)^3=62208
X^3+8x^3+27x^3=62208
36x^3=62208
X cube=62208 divided by 36
X cube= 1728
X=12
Thus the numbers are x,2x,3x=12,24,36
X:2X:3X=1:2:3
Given that ,
(X)^3+(2x)^3+(3x)^3=62208
X^3+8x^3+27x^3=62208
36x^3=62208
X cube=62208 divided by 36
X cube= 1728
X=12
Thus the numbers are x,2x,3x=12,24,36
Answered by
9
The numbers are 12 , 24 and 36 .
Hope this will help you.
Hope this will help you.
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