three numbers could have a total of 103
Answers
Answer: To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
Explanation:
X + X + 1 + X + 2 = 103
3X + 3 = 103
3X + 3 - 3 = 103 - 3
3X = 100
3X/3 = 100/3
X = 33 1/3
Since 33 1/3 is not an integer, there is no true answer to this problem.
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What three consecutive integers have a sum of 103?
Three Consecutive Integers
Here we will use algebra to find three consecutive integers whose sum is 103. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 103. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 103
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 103
3X + 3 = 103
3X + 3 - 3 = 103 - 3
3X = 100
3X/3 = 100/3
X = 33 1/3
Since 33 1/3 is not an integer, there is no true answer to this problem.
However, there are three numbers that add up to 103. The first number is (33 1/3), the second number is (33 1/3) + 1, and the third number is (33 1/3) + 2. Therefore, we could make this the answer to "Three consecutive numbers that add up to 103 are?":
33 1/3 + 34 1/3 + 35 1/3 = 103