Three numbers have a sum of 27. The first number is half as much as the 3rd number. The second number is 1 less than twice the 3rd number. What is the LARGEST of the 3 numbers?
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plz mark as brillient
Step-by-step explanation:
Let the third number be x.
Then, second number be =3x
First number be =2×3x=6x
Given that,
Average of three numbers =40
Sum of three numbers =40×3=120
According to the question,
x+3x+6x=120
10x=120
x=12
Difference between largest and smallest numbers
=6x−x=5x=5×12=60.
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