Three numbers P,Q and R are in the ratio 3:4:5. if 15 is subtracted from P ,5 is added to Q and 10 is added to R the ratio between the new numbers become 1:3:4 respectively .what is the value of Q?
Answers
Given :- Three numbers P,Q and R are in the ratio 3:4:5. if 15 is subtracted from P ,5 is added to Q and 10 is added to R the ratio between the new numbers become 1:3:4 respectively .what is the value of Q ?
Solution :-
Let us assume that, P is 3x , Q is 4x and R is 5x.
given that,
- 15 is subtracted from P .
- 5 is added to Q .
- 10 is added to R.
So,
→ New P = (3x - 15)
→ New Q = (4x + 5)
→ New R = (5x + 10) .
given that,
- The new number becomes in ratio = 1 : 3 : 4 .
Therefore,
→ (3x - 15) : (4x + 5) : (5x + 10) = 1 : 3 : 4.
→ (3x - 15) / (4x + 5) = 1/3
→ 3(3x - 15) = (4x + 5)
→ 9x - 45 = 4x + 5
→ 9x - 4x = 5 + 45
→ 5x = 50
dividing both sides by 5,
→ x = 10.
Hence,
→ value of Q = 4x = 4 * 10 = 40 (Ans.)
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Answer:
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