Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
a.75 b81 c85 d89
Answers
Answer:
Step-by-step explanation:
As given the questions these numbers are co primes, so there is only 1 as their common factor.
It is also given that two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
So first number is : 551/29 = 19
Third number = 1073/29 = 37
So sum of these numbers is = (19 + 29 + 37) = 85
Given :
•3 numbers which are co-prime to each other such that the product of the 1st two numbers is 551 and that of the last 2 is 1073.
To find :
• The sum of 3 numbers?
Calculations :
★ Taking HCF (Higest common factor) for 551 and 1073.
= HCF = 29 ---(1)
★ Dividing the first number and last number by the 29, we get:
= 551/29
= 19 ---(2)
= 1073/29
= 37 ---(3)
★ As per the last case, sum of three numbers, we get:
= 29 + 19 + 37
= 85
★ Therefore, the sum of three numbers is equal to 85.