Three pipes a, b and c can fill a tank from empty to full in 30 minutes, 20 minutes and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, b and c discharge chemical expiations p, q and r respectively. What is the proportion of expiation r in the liquid in the tank after 3 minutes?
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Answer:
Step-by-step explanation:6/11
Description for Correct answer:
Total quantity of solutions P, Q and R
from A, B and C respectively, after 3 min
= 330+320+310=3(2+3+660)
= 3×1160=1120
Quantity of solution R in liquid in 3 min = 310
Therefore, Part of solution R
= 101120=3×2010×11=6/11
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