Question

Three numbers which are co-prime to one another are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is select one:

Answer 1

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Since the numbers are co-prime, they contain only 1 as the common factor.

Also, the given two products have the middle number in common.

So, middle number = H.C.F. of 551 and 1073 = 29;

First number =(551/29)= 19;    Third number =(1073/29)= 37.2929

Required sum = (19 + 29 + 37) = 85.



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Answer 2

Given :

•3 numbers which are co-prime to each other such that the product of the 1st two numbers is 551 and that of the last 2 is 1073.

To find :

• The sum of 3 numbers?

Calculations :

★ Taking HCF (Higest common factor) for 551 and 1073.

= HCF = 29 ---(1)

★ Dividing the first number and last number by the 29, we get:

= 551/29

= 19 ---(2)

= 1073/29

= 37 ---(3)

★ As per the last case, sum of three numbers, we get:

= 29 + 19 + 37

= 85

★ Therefore, the sum of three numbers is equal to 85.