three numbers whose sum is 15 in AP. if 1,3,9 are added respectively to the numbers the resulting number are in GP. find the numbers
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Step-by-step explanation:
let the numbers be: a-d , a , a+d
3a = 15 , a = 5
the number are : 5-d , 5 , 5+d
then by adding 1, 3 , 9
the new numbers will be : 6-d , 8 , 14+d ,
64 = ( 14+d ) (6-d ) = 84 - 8d - d²
d²+ 8d - 20 = 0
(d +10)(d-2) = 0
d = -10 , 2
case 1 , d = -10
the numbers are 15 , 5 , -5
case2 , d = 2
the numbers are 3 , 5 , 7
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