Three numbers whose sum is 18 are in AP. if 2,4 ,11 are added to them respectively the resulting number are in GP find the numbers.
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16
Answer:
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Step-by-step explanation:
let numbers are a-d,a,a+d
A.T.Q.
a-d+a+a+d=18
3a=18
a=6
again A.T.Q
6-d+2,6+4,6+d+11 are in G.P.
so
8-d,10 and 17+d are in G.P.
10/8-d=17+d/10
(17+d)(8-d)=100
136+8d-17d-d^2=100
d^2+9d-36=0
d^2+12d-3d-36=0
d(d+12)-3(d+12)=0
d=3,-12
if d=3
numbers are 6-3,6,6+3
I.e.3,6,9
if d=-12
numbers are 18,6,-6
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