Physics, asked by krishnajiapte225, 2 months ago

three parallel conducting plates a b c having charges 3C 2c and C respectively are placed parallel to each other at charge + Q is put near the 3C plate then the electric electric field we will be in the direction of​

Answers

Answered by AnanthAkshatha01
1

Answer:

Three identical parallel conducting plates A, B and C are placed as shown. Switches S_1 and S_2 are open, and can connect A and C to earth when closed. +Q charges is given to B.

Answered by AnanthAkshay01
0

Explanation:

Given:

Repulsive force of magnitude 6 × 10−3 N

Charge on the first sphere, q1 = 2 × 10−7 C

Charge on the second sphere, q2 = 3 × 10−7 C

Distance between the spheres, r = 30 cm = 0.3 m

Electrostatic force between the spheres is given by the relation:

F = (1/4πε0). (q1q2)/ (r2)

Where, ε0 = Permittivity of free space and (1/4πε0) =9 × 109 Nm2C−2

Therefore, force F = (9 × 109 × 2 × 10−7)/ ((0.3)2)

= 6 × 10−3N

Hence, force between the two small charged spheres is 6 × 10−3 N. The charges are of same nature. Hence, force between them will be repulsive.

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