Question

Three particles a, b and c are situated at the vertices of an equilateral triangle abc of side d at t = 0. Each of the particles moves with constant speed v. A always has its velocity along ab, b along bc and c along ca. At what time will the particles meet each other general formulae

Answer 1

Answer:

The time the particles will meet each other is 2d/3v

Explanation:

There are three particles, a,b,c.

They situated in a equilateral triangle abc of side d at t=0.

therefore, ab=bc=ca=d

Now each of the particles moves with constant speed v.

let, the length of each edge is x

a is making angle of cos 120 degree with bc as it is an equilateral triangle.

The rate by which a approaches b, b approaches c and c approaches a,

-dx/dt= v-v cos(2π /3)

-∫dx(the limit is from d to 0)=  3v/2 ∫dt (the limit is from 0 to t)

d=3/2vt

=> t= 2d/3v

Answer 2

2d/3v

Explanation:

hope this helps you.plz mark me as brainliest and follow me