Question

Three people A, B and C are standing at the vertices of an equilateral triangle. They start travelling towards each other in such a way that A is always moving towards C, C is always moving towards B and B is always moving towards A at a speed of 15m/s. If the side of the triangle is 60m, find the difference between the length of the path travelled by A and the shortest distance between the starting and ending points.
A.303030
B.60(3+1)60(\sqrt{3} +1)60(3​+1)/3\sqrt{3}3​
C.60(3−1)60(\sqrt{3} - 1)60(3​−1)/3\sqrt{3}3​
D.60(3−1)60(\sqrt{3} - 1)60(3​−1)/606060

Answer 1

for equilateral triangle all distance is same