Question

Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue?

Answer 1

Correct option is C. 28

Option (B) is the correct answer

Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. Butsince there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possiblearrangements i.e., CBA and CAB.