Question

Three persons A, B and C invested different amounts in a fixed deposit scheme for one year at the rate of 12% per
annum and earned a total interest of $3,240 at the end of the year. If the amount invested by B is $5,000 more than
the amount invested by A and total amount invested by A and C is $2,000 more than the amount invested by B,
then what is the amount invested by B?​​

Answer 1

Answer:

Let the amount invested by amar be x and that by Akbar be(5000+x) and Anthony invested (5000+2000+ x)

therefore by formula simple interest = P*R*N/1000

12x/100 +(5000+x)12x/100 +(7000+x)12x/100

we get by solving x = 5000

so the amount invested by Akbar is 5000 +x =10000

Step-by-step explanation:

Answer 2

Answer:

Amount invested by B = 12500

Given:Three persons A, B, and C invested different amounts in a fixed deposit scheme for one year at the rate of 12% per annum and earned a total interest of $3,240 at the end of the year. If the amount invested by B is $5,000 more than the amount invested by A and the total amount invested by A and C is $2,000 more than the amount invested by B.

To find: Amount invested by B

Solution: simple interest = p × r × t

p - principal amount, r - rate, t - time

= p × 0.12 × 1 = $3,240

= p = 3240 / 0.12

= p = 27000( total amount invested)

let the amount invested by

A - p1, B - p2, C - p3

p2 = p1 + 5000

p1 + p3 = 2000 + p2

= p1 + p3 = 2000 + 5000 + p1

= p3 = 2000 + 5000 + p1 -p1

= p3 = 7000

p1 + p2 = 27000 - 7000

p1 + p2 = 20000

p1 = 20000 - p2

p1 = 20000 - (5000 + p1)

p1 = 20000 - 5000 - p1

2p1 = 15000, p1 = 7500( 15000/2 )

p2 = 5000 + p1 (7500)

p2 = 5000 + 7500 = 12500

p1 + p2 + p3 = 27000

simple interest = 27000 × 12/100 = 3240

Amount invested by B = 12500

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