Question

three persons a b c are standing on a vertices of equilateral triangle start moving with constant speed V such that velocity of Ais always your directly towards a person Band velocity of B is directly towards C and so on find the time and they will meet

Answer 1

they meet at centroid. if side is d then component of v along line joining side with centroid is vcos30. t= (d/root(3))/ vcos30= 2d/ 3v

Answer 2

Hii,

formula-> t= d/v*(1-cos π/n)
Where n= no. Of persons

t= d/v(1-cos2π/3)

t=d/v[1-(-1/2)] = 2d/3v

Hope this helps..