Question

three persons R, S, T run a race S finishes 36m ahead of T and 48m ahead of R. while T finished 16m ahead of R. if each of them runs the entire distance at their respective constant speeds, what is the length of the race​

Answer 1

Answer:

the length of the race​ = 144 m

Step-by-step explanation:

Let the length of the race be 'd'. m

When S finished the race, T and R would have run (d−36) and (d−48) meters respectively.

When T finishes the race, R would have run (d−16) meters.

The ratio of speeds of T and R is:

(d−36)/(d−48)= d/(d−16)

=> (d - 16)(d - 36) = d(d - 48)

=> d² - 52d + 16*36 = d² - 48d

=> 4d = 16 * 36

=> d = 16 * 9

=> d = 144

the length of the race​ = 144 m