Question

Three pieces of timber, 42-m, 49-m and 63-m long, have to be divided into planks of the same length. What is the greatest possible length of each plank?​

Answer 1

Answer:

7m

Step-by-step explanation:

The length of 3 pieces of timber are 42m, 49m, 63m respectively. We have to divide the timber into equal length.

Therefore greatest possible length of each plank = HCF (42,49,63)

Prime factorization

42 = 2*3*7

49 = 7*7

63 = 3*3*7

Therefore HCF = Product of the smallest power of each common prime factor involved in the number = 7

Hence, the greatest possible length of each plank is 7m.