Math, asked by souvik2662, 4 months ago


Three pipes A, B and C can fill a cistern in 6 hours. After working together for 2 hours, C is
closed and A and B fill the cistern in 8 hours. Find the time in which the cistern can be filled by
pipe C.

Answers

Answered by niralneetalshah1208
1

Answer:

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Step-by-step explanation:

now see

A B C together fill cistern in 6h

so in 1hr ABC fill 16th of cistern

so in 2 hrs 13rd of cistern will be filled when ABC are together

so A B will fill the remaining 23rd of cistern in 8hrs

so in 1hr AB will fill 2(3∗8)th of the cistern

so in 1hr AB will fill 112th of the cistern

let C takes x hours to fill the tank

then in 1hr C will fill 1xth part of cistern

now cistern filled in 1hr by ABC = cistern filled by AB in 1hr + cistern filled by C in 1hr

so

16=112+1x

1x=16−112

1x=848−448

1x=448

1x=112

so x = 12

so it seems C will take 12hrs to fill the cistern on its own

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