Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
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C alone can fill it in 14 hours
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Answer:
C can fill the whole tank in 14 hours.
Explanation:
Part of the tank filled by (A + B + C) in 2 hours = 2 × 1/6 = 1/3
Remaining part = 1 - 1/3 = 2/3
∴ 2/3rd of the tank is filled by (A + B) in 7 hours.
∴ The whole tank is filled by (A + B) in ( 7 × 3/2 ) hours = 21/2 hours.
∴ Part of the tank filled by C in 1 hour = Part of the tank filled by (A + B + C) in 1 hour - Part of the tank filled by (A + B) in 1 hour = 1/6 - 2/21 = 3/42 = 1/14
∴ C can fill the whole tank in 14 hours.
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