Math, asked by mgkbebo, 7 days ago



Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:

Answers

Answered by adityawaghamode100
2

Answer:

Solution

verified

Verified by Toppr

Correct option is C)

Part time in 2 hours=

6

2

=

3

1

Remaining part=(1−

3

1

)=

3

2

.

∴(A+B)'s 7 hour's work=

3

2

(A+B)'s 1 hour's work=

21

2

∴ C's hour's work={(A+B+C)'s 1 hour's work}−{(A+B)'s 1 hour's work}

=(

6

1

21

2

)=

14

1

∴ C alone can fill the tank in 14 hours.

Similar questions