Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
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Correct option is C)
Part time in 2 hours=
6
2
=
3
1
Remaining part=(1−
3
1
)=
3
2
.
∴(A+B)'s 7 hour's work=
3
2
(A+B)'s 1 hour's work=
21
2
∴ C's hour's work={(A+B+C)'s 1 hour's work}−{(A+B)'s 1 hour's work}
=(
6
1
−
21
2
)=
14
1
∴ C alone can fill the tank in 14 hours.
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