Question

three pipes can fill an empty tank in 3 hours 4 hours and 6 hours respectively. how long would they take to fill the empty tank if all of them are opened together
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Answer 1

Answer:

There work capacities will be 1/3 , 1/4 and 1/6 respectively

There combined work capacity

=

$x = \frac{1}{3} + \frac{1}{4} + \frac{1}{6} = \frac{4 + 3 + 2}{12} = \frac{3}{4}$

So time

$= \frac{1}{x} = \frac{4}{3} hrs = 1 \: hr \: 20 \: min$

Answer 2

Answer:1 hour 20 min.

Step-by-step explanation:

Time taken =1/3+1/4+1/6

=4+3+2/12

=9/12

=3/4

Now , this will divided by 1 which will result in 4/3 hours.