Question

31 A sphere of mass 40 kg is attracted by a second sphere
of mass 15 kg when their centres 320 cm apart with a
force of 0.1 milligram weight. Calculate the value of
gravitational constant. [Ans. 1.7 X10-8N- m²/kg? 1​

Answer 1

Answer:

m₁ = 40 kg

m₂ = 15 kg

r = 320 cm

= 3.2 m

Force = 0.1mg

0.1*10⁻³*980 dyne

98*10⁻³dyne

98*10⁻⁸N

F = Gm₁m₂/r²

9.8*10⁻⁷ = 600G/10.24

[(98*10.24).10⁻⁸] / 600 = G

[1003.52/600] . 10⁻⁸ = G

1.672*10⁻⁸ N.m²/kg⁻² = G

or,

1.7*10⁻⁸ N.m²/kg⁻² = G

I hope this helps.