in how many years will a sum amount to be 2.5 times of itself at 9% p.a. compound intrest
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Answer:
Let p be the principal. Then:
2.5p=p[(1+0.09)^y] where y is the time, in years. So:
2.5p/p=1.09^y
log 2.5=log 1.09^y
=y log 1.09
y=1og 2.5/ log 1.09
=10.63257399 years
Step-by-step explanation:
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