CBSE BOARD XII, asked by NikhilAnubha, 1 year ago

three point charges q q minus Q are placed at the vertices of an equilateral triangle of side length L find the magnitude of the acting on the first charge

Answers

Answered by Anonymous
3
sorry i didnt get your questions can u plzz attach thr image of the question as well
Answered by Anonymous
0

The magnitude of the force acting on the first charge is  \frac{q^{2} }{4\pi el^{2} }

This can be proved as follows:

  • Let force on the first charge be represented as q
  • Now, the force acting on the first charge will be  F =  \frac{q^{2} }{4\pi el^{2} }
  • Where,
  1. q is the charge.
  2. π is equivalent to 3.14159.
  3. e is the epsilon and equivalent to 8.854 × 10⁻¹² farads per meter.
  4. l is the length of the sides of the triangle.
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