Question

Three point masses A,B and C are 66g each are connected. The acceleration of system is 5 meter per second square. Tension between B and C approximately is :
(11th NEET Syllabus) Please let me know the answer with appropriate explanation :)

Answer 1

Tension force between B and C is pulling the block C

so here tension force is the net force on block C

So we will say

$F_{net} = ma$

here net force on block C is tension force

m = mass of block C = 66 kg

a = acceleration of block C = 5 m/s^2

now we have

$T = 66 * 5$

$T = 330 N$

so the tension in the connecting rope is 330  N