Physics, asked by Dolly6471, 10 months ago

Three points charges +q each kept at the vertices of an equilateral triangle of side of l. Determine the magnitude and sign of the charge to be kept at its centroid so that the charges at the vertices remain in equilibrium.​

Answers

Answered by harshchhawal233
0

Answer:

The charge at any vertex will remain in equilibrium if the net force experienced by this charge due to all other three charges is zero.

Let Q be the required charge to be kept at the centroid G.

Considering the charge at A,

Force

F

1

on charge at A due to charge at B

F

1

=

4πϵ

0

1

a

2

q

2

along

BA

Force

F

2

on charge at A due to charge at C

F

2

=

4πϵ

0

1

a

2

q

2

along

CA

Since angle between

F

1

and

F

2

is 60

.

F

1

+

F

2

=

3

4πϵ

0

1

a

2

q

2

along

GA

Also, the distance of centroid G from any vertex is

3

a

The nature of charge to be kept at G has to be opposite (−ve) so that it exerts a force of attraction on charge (+q) kept at A to balance the force

F

1

+

F

2

Force exerted by (−Q) kept at G on charge (+q) at A=

4πϵ

0

1

(

3

a

)

2

Qq

=

4πϵ

0

1

a

2

Q.3q

along

AG

Equating the two forces, being equal and opposite.

3

4πϵ

0

1

a

2

q

2

=−

4πϵ

0

1

a

2

3Qq

⇒Q=−

3

q

.

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