Question

Three positive integers aj, az and az are in
AP, such that a1 + a2 + a3 = 33 and
a1 xa2 x a3 =1155. Find the integers a1,a2 and a3
​

Answer 1

Answer:

7,11,15 or 15,11,7

Step-by-step explanation:

this is the answer

Answer 2

Answer:

11 , 15 and 7 is your answer mate

Step-by-step explanation:

$11 + 15 + 7 = 33 \\ 11 \times 15 \times 7 = 1155$

Hope my answer helps you :-)