Question

three real numbers x,y,z are such that x²+6y=-17,y²+4z=1,z²+2x=2. what is the value of x²y²+z²=?​

Answer 1

Answer:

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Step-by-step explanation:

x2 + 2x + y2 + 6y + z2 + 4z = -14

x2 + 2x + 1 + y2 + 6y + 9 + z2 + 4z + 4 = 0

( x + 1 )2 + ( y + 3 )2 + ( z + 2 )2 = 0

x = -1 , y = -3 , z = -2

x2 + y2 + z2 = 14