Question

three resistance 5,10 and 30 are connected in parrellel calculate the total resistance of the circuit​

Answer 1

Explanation:

A: According to Ohm's law

V= IR

that implies

I = V/R

NOW; I ( 5 ohm ) = 6/5 = 1.2 A ...........(1)

I ( 10 ohm) = 6/10 = 0.6 A ........... (2)

I ( 30 ohm) = 6/30 = 0.2 A ............ (3)

B: the total current in the circuit is (1) + (2) +(3) ( total current is the sum of current across each resistor)

So , I ( total ) = 1.2 + 0.6 + 0.2 = 2 A

C: total resistance in parallel is

1/Re = 1/R1 + 1/R2 + 1/R3 ( R1 IS 5 ohms ,R2is 10 ohms , and R3 is 30 ohms )

That will give you

Re= 3 ohms

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