three resistance each of 8 ohm are connected to a triangle. the resistance between any two terminal Will be ?
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Consider A, B and C to be the three vertices of the triangle.
To determine the equivalent resistance between terminals, say A and B, the resistances in the arm BC and AC will be in series = 8 + 8 = 16 Ω.
This 16 Ω will be in parallel to the 8 Ω resisteance.
Hence, the required resistance will be
1/R=1/8+1/16=3/16
⇒R = 16/3 Ω
To determine the equivalent resistance between terminals, say A and B, the resistances in the arm BC and AC will be in series = 8 + 8 = 16 Ω.
This 16 Ω will be in parallel to the 8 Ω resisteance.
Hence, the required resistance will be
1/R=1/8+1/16=3/16
⇒R = 16/3 Ω
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Answer:
three resistence each of 8 ohm r connected to a ∆
Explanation:
the resistence btw any two terminal will be 16/3 ohm...
Hope this will help u...
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