three resistance of 10 ohm 15 ohm 20 ohm are connected in series in a circuit if the potential drop across the resistance of 3 volt find the current in the circuit find the potential across 10 Ohm
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Series connection means that the resistances are added. Therefore, Equivalent Resistance= (10+15+20)Ω=45Ω
Given that the potential drop across the resistances is 3V, then by Ohm's Law:
V=IR
3V=I×45Ω
I=(1/15)A
In a series connection, the current flowing through all the resistances is the same. So, (1/15)A of current also flows through 10Ω resistance. By Ohm's Law:
V=I×R
V=(1/15)(10)
=(2/3)V
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