Question

Three resistance of 2Omega 3 Omega and 6 Omega are connected in series and parallel calculate the ratio of the effective resistance of wire and combination of resistance

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Answer 1

Answer:Rs= R1+R2+R3

2+3+6=11ohm( effective resistance in series)

1/To=1/R1+1/R2+1/R3

1/2+1/3+1/6

6/12+4/12+2/12

=12/12=1ohm(effective resistance in parallel)

Answer 2

when they're connected in series :-

R1+R2+R3

=> 11 ohm

when connected in parallel :-

1/R = 1/R1 + 1/R2 + 1/R3

=> 1/R = 1/2+1/3+1/6

=> R = 1 Ohm

So their ratio will be 11:1